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Reserves estimation
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Revision as of 21:25, 19 October 2014
190 bytes removed
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21:25, 19 October 2014
→Production history analysis
Line 241:
Line 241:
|+ {{table number|3}}Decline equations
|+ {{table number|3}}Decline equations
|-
|-
−
! Solving for
+
! Solving for
||
Exponential
||
Hyperbolic
−
!
Exponential
−
!
Hyperbolic
|-
|-
−
| Rate of production
+
| Rate of production
|
| ''q''<sub>t</sub> = ''q''<sub>i</sub> ''e''<sup>– ''Dt''</sup> |
|
<
math
>
q_{
t
}
=
q_{\rm
i
}
(1 +
nD_{\rm
i
}
t)
^{-1
/n
}
</
math
>
−
| ''q''<sub>t</sub> = ''q''<sub>i</sub> ''e''<sup>– ''Dt''</sup>
−
|
''q''
<
sub
>t
</sub>
=
''q''<sub>
i
</sub>
(1 +
''nD''<sub>
i
</sub> ''
t
''
)
<sup>–1
/
''
n
''
</
sup
>
|-
|-
−
| Cumulative production
+
| Cumulative production
|
| ''N<sub>p</sub>'' = ( ''q''<sub>i</sub> – ''q<sub>t</sub>'' )/ ''D'' |
|
−
| ''N<sub>p</sub>'' = ( ''q''<sub>i</sub> – ''q<sub>t</sub>'' )/ ''D''
+
<math> N_{\rm p} = q_{\rm i}^{n}/[(1 - n)D_{\rm i}](q_{\rm i}^{1 - n} - q_{\rm t}^{1-n})</math>
−
|
<math> q_{t} = q_{\rm i}(1 + nD_{\rm i}t)^{-1/n}</math><br />
−
<math> N_{\rm p} = q_{\rm i}^{n}/[(1 - n)D_{\rm i}](q_{\rm i}^{1 - n} - q_{\rm t}^{1-n})
</math><br />
−
<math>t = [(q_{\rm i}/q_{\rm ec})^{n} - 1/nD_{\rm i}
</math>
|-
|-
−
| Life of reservoir
+
| Life of reservoir
|
| ''t'' = (1/ ''D'' )ln( ''q''<sub>i</sub> / ''q''<sub>ec</sub> ) |
| <math>
t = [(
q_{\rm
i
}
/
q_{\rm
ec
}
)
^{
n
} -
1/
nD_{\rm
i
}
</
math
>
−
| ''t'' = (1/ ''D'' )ln( ''q''<sub>i</sub> / ''q''<sub>ec</sub> )
−
|
''
t
''
= [(
''q''<sub>
i
</sub> ''
/
q''<sub>
ec
</sub>
)
''<sup>
n
</sup>'' –
1/
''nD''<sub>
i</
sub
>
|}
|}
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