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8 bytes added ,  20:41, 11 November 2014
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'''''Example''''': Assume a well has taken a kick at [[depth::10,000 ft]] while drilling with 11.5-ppg mud. The well is shut-in, and the drill pipe pressure reads 312 psi. The excess in pounds per gallon mud weight equivalent is calculated as follows:
 
'''''Example''''': Assume a well has taken a kick at [[depth::10,000 ft]] while drilling with 11.5-ppg mud. The well is shut-in, and the drill pipe pressure reads 312 psi. The excess in pounds per gallon mud weight equivalent is calculated as follows:
   −
:<math>\mbox{MW} = 312/(0.052 \times 10{,}000) = 0.6 \mbox{ ppg}</math>
+
:<math>\mbox{MW} = \frac{312}{(0.052 \times 10{,}000)} = 0.6 \mbox{ ppg}</math>
    
Adding the calculated excess of 0.6 ppg to the current mud weight of 11.5 ppg results in 12.1 ppg necessary to control the well. The mud weight is typically increased beyond the calculated kill weight to allow for the negative pressure (swab) exerted on the hole when tripping the drill string.
 
Adding the calculated excess of 0.6 ppg to the current mud weight of 11.5 ppg results in 12.1 ppg necessary to control the well. The mud weight is typically increased beyond the calculated kill weight to allow for the negative pressure (swab) exerted on the hole when tripping the drill string.

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