Changes

:<math>h_{\rm A}  = 2369/0.433 - 5160 = 311 \mbox{ ft}</math>

:<math>h_{\rm A}  = 2369/0.433 - 5160 = 311 \mbox{ ft}</math>

:<math>h_{\rm B} &= 2324/0.433 - 5090 = 277 \mbox{ ft}\\h_{\rm C} &= 2400/0.433 - 5300 = 243 \mbox{ ft}</math>

:<math>h_{\rm B} = 2324/0.433 - 5090 = 277 \mbox{ ft}</math>

:<math>h_{\rm C} = 2400/0.433 - 5300 = 243 \mbox{ ft}</math>

[[file:fluid-contacts_fig3.png|thumb|{{figure number|3}}Example of calculating hydrodynamic fluid contacts from pressure data. Pressure elevations are shown by arrows. Calculated fluid contacts are shown by thin lines.]]

[[file:fluid-contacts_fig3.png|thumb|{{figure number|3}}Example of calculating hydrodynamic fluid contacts from pressure data. Pressure elevations are shown by arrows. Calculated fluid contacts are shown by thin lines.]]

:<math>h_{\rm A} - h_{\rm B}/2 \mbox{ mi}  = 17 \mbox{ ft/mi}</math>

:<math>h_{\rm A} - h_{\rm B}/2 \mbox{ mi}  = 17 \mbox{ ft/mi}</math>

:<math>h_{\rm B} - h_{\rm C}/2 \mbox{ mi} &= 17 \mbox{ ft/mi}</math>

:<math>h_{\rm B} - h_{\rm C}/2 \mbox{ mi} = 17 \mbox{ ft/mi}</math>

The Potentiometric gradient is approximately constant along the section at 17 ft/mi. Calculating the contact dip from Equation (2), we have

The Potentiometric gradient is approximately constant along the section at 17 ft/mi. Calculating the contact dip from Equation (2), we have

:<math>\mbox{oil--water tilt}  = 1.0/(1.0 - 0.8) \times 17 = 85 \mbox{ ft/mi}</math>

:<math>\mbox{oil--water tilt}  = 1.0/(1.0 - 0.8) \times 17 = 85 \mbox{ ft/mi}</math>

:<math>\mbox{gas--oil tilt} &= 1.0/(1.0 - 0.15) \times 17 = 20 \mbox{ ft/mi}</math>

:<math>\mbox{gas--oil tilt}   = 1.0/(1.0 - 0.15) \times 17 = 20 \mbox{ ft/mi}</math>

The fluid contacts are graphically projected away from well B at the calculated dips to determine the contact elevations along the cross section.

The fluid contacts are graphically projected away from well B at the calculated dips to determine the contact elevations along the cross section.