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9 bytes added ,  20:42, 11 November 2014
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'''''Example''''': Assume a leak-off test conducted in a 10,000-ft wellbore containing 11.5-ppg mud with a leak-off pressure of 1040 psi. The formation fracture pressure is estimated as
 
'''''Example''''': Assume a leak-off test conducted in a 10,000-ft wellbore containing 11.5-ppg mud with a leak-off pressure of 1040 psi. The formation fracture pressure is estimated as
   −
:<math>\mbox{MW} = 1040/(0.052 \times 10{,}000 = 2.0 \mbox{ ppg}</math>
+
:<math>\mbox{MW} = \frac{1040}{(0.052 \times 10{,}000)} = 2.0 \mbox{ ppg}</math>
    
The formation fracture pressure is equivalent to an 11.5 + 2.0 = 13.5 ppg mud weight, or
 
The formation fracture pressure is equivalent to an 11.5 + 2.0 = 13.5 ppg mud weight, or

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