10,323
edits
Changes
Jump to navigation
Jump to search
Line 111:
Line 111: − +
→Hydrostatic pressure in liquid columns
:<math>\mbox{MW} = \frac{\mbox{P}}{(0.052 \times \mbox{D})}</math>
:<math>\mbox{MW} = \frac{\mbox{P}}{(0.052 \times \mbox{D})}</math>
''Example'': Assume a formation at [[depth::10,000 ft]] has a known hydrostatic pressure of 6292 psi. The mud weight needed to drill this formation “balanced” (hydrostatic pressure equal to formation pressure) is calculated as follows:
'''''Example''''': Assume a formation at [[depth::10,000 ft]] has a known hydrostatic pressure of 6292 psi. The mud weight needed to drill this formation “balanced” (hydrostatic pressure equal to formation pressure) is calculated as follows:
:<math>\mbox{MW} = \frac{6292}{(0.052 \times 10{,}000)} = 12.1 \mbox{ ppg}</math>
:<math>\mbox{MW} = \frac{6292}{(0.052 \times 10{,}000)} = 12.1 \mbox{ ppg}</math>