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→Production history analysis
! Solving for || Exponential || Hyperbolic
! Solving for || Exponential || Hyperbolic
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| Rate of production || ''q''<sub>t</sub> = ''q''<sub>i</sub> ''e''<sup>– ''Dt''</sup> || <math> q_{t} = q_{\rm i}(1 + nD_{\rm i}t)^{-1/n}</math>
| Rate of production || <math>q_t = q_{\text{i}}e^{-Dt}</math> || <math> q_{t} = q_{\rm i}(1 + nD_{\rm i}t)^{-1/n}</math>
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| Cumulative production || ''N<sub>p</sub>'' = ( ''q''<sub>i</sub> – ''q<sub>t</sub>'' )/ ''D'' ||
| Cumulative production || ''N<sub>p</sub>'' = ( ''q''<sub>i</sub> – ''q<sub>t</sub>'' )/ ''D'' ||