Changes
Jump to navigation
Jump to search
← Older edit
Newer edit →
Reserves estimation
(view source)
Revision as of 20:06, 29 October 2014
5 bytes added
,
20:06, 29 October 2014
→Production history analysis
Line 225:
Line 225:
| Rate of production || <math>q_t = q_{\text{i}}e^{-Dt}</math> || <math> q_{t} = q_{\rm i}(1 + nD_{\rm i}t)^{-1/n}</math>
| Rate of production || <math>q_t = q_{\text{i}}e^{-Dt}</math> || <math> q_{t} = q_{\rm i}(1 + nD_{\rm i}t)^{-1/n}</math>
|-
|-
−
| Cumulative production ||
''N
<
sub
>
p</sub>''
= (
''q''<sub>
i</
sub
>
– ''q<sub>t</sub>'' )/ ''D''
||
+
| Cumulative production || <
math
>
N_p
=
\frac{
(
q_{\text{
i
}} - q_t)}{D}
</
math
> || <math> N_{\rm p} = q_{\rm i}^{n}/[(1 - n)D_{\rm i}](q_{\rm i}^{1 - n} - q_{\rm t}^{1-n})</math>
−
<math> N_{\rm p} = q_{\rm i}^{n}/[(1 - n)D_{\rm i}](q_{\rm i}^{1 - n} - q_{\rm t}^{1-n})</math>
|-
|-
−
| Life of reservoir ||
''
t
''
= (1
/ ''
D
''
)ln(
''q''<sub>
i
</sub> / ''q''<sub>
ec<
/sub
>
)
|| <math>t = [(q_{\rm i}/q_{\rm ec})^{n} - 1/nD_{\rm i}</math>
+
| Life of reservoir ||
<math>
t =
\left
(
\frac{
1
}{
D
} \right
) ln
\left
(
\frac{q_{\text{
i
}}}{q_{
ec
}} \right)
<
\math
> || <math>t = [(q_{\rm i}/q_{\rm ec})^{n} - 1/nD_{\rm i}</math>
|}
|}
Cwhitehurst
Bureaucrats
,
Interface administrators
,
Administrators
10,372
edits
Navigation menu
Personal tools
Log in
Namespaces
Page
Discussion
Variants
Views
Read
View source
View history
More
Search
Navigation
Main page
Recent changes
Random page
Help pages
Tools
Special pages
Printable version